Download a free Class 8 Maths worksheet on Algebraic Expressions with MCQs, fill in the blanks and short answer questions. Complete answer key included. Personalized to your class, subject and chapter.
Q1. Which of the following is a binomial?
a) x + y + z
b) x² + 2x + 1
c) 3x + 5
d) 7xy
Q2. The product of (x + 3) and (x - 3) is:
a) x² + 9
b) x² - 9
c) x² - 6x + 9
d) x² + 6x - 9
Q3. The value of (2x + 3y)² is:
a) 4x² + 9y²
b) 4x² - 12xy + 9y²
c) 4x² + 12xy + 9y²
d) 2x² + 12xy + 3y²
Q4. Which identity is used to expand (a + b)(a - b)?
a) (a + b)² = a² + 2ab + b²
b) (a - b)² = a² - 2ab + b²
c) a² - b² = (a + b)(a - b)
d) (a + b)² = a² - 2ab + b²
Q5. The coefficient of xy in the expression 5x²y + 3xy - 7xy² is:
a) 5
b) -7
c) 3
d) 0
Q6. The number of terms in the expression 4x² + 3xy - 7y + 5 is ________.
Q7. The product of (x + 5)² using the identity gives the expansion x² + 10x + ________.
Q8. The value of (103)² calculated using the identity (100 + 3)² is ________.
Q9. When we multiply a monomial by a binomial, the result is obtained by using the ________ property.
Q10. The expression (a - b)² = a² - 2ab + b² is called an algebraic ________.
Q11. Find the product of (2x + 5) and (3x - 2).
Q12. Expand (4a - 3b)² using a standard identity.
Q13. Find the value of 99² using the identity (100 - 1)².
Q14. Add the following algebraic expressions:
3x² + 5xy - 2y² and x² - 3xy + 4y²
Q15. Simplify: (x + 4)(x + 6) - (x + 2)(x + 3)
Section A: Multiple Choice Questions
Q1. Answer: c) 3x + 5
Reason: A binomial has exactly two terms.
Q2. Answer: b) x² - 9
Reason: Using identity (a + b)(a - b) = a² - b², we get x² - 9.
Q3. Answer: c) 4x² + 12xy + 9y²
Reason: (2x + 3y)² = (2x)² + 2(2x)(3y) + (3y)² = 4x² + 12xy + 9y²
Q4. Answer: c) a² - b² = (a + b)(a - b)
Reason: This is the standard identity for difference of two squares.
Q5. Answer: c) 3
Reason: In the term 3xy, the coefficient of xy is 3.
Section B: Fill in the Blanks
Q6. 4
Q7. 25
Q8. 10609
Q9. Distributive
Q10. Identity
Section C: Short Answer Questions
Q11. (2x + 5)(3x - 2)
= 2x(3x - 2) + 5(3x - 2)
= 6x² - 4x + 15x - 10
= 6x² + 11x - 10
Q12. (4a - 3b)²
Using (a - b)² = a² - 2ab + b²
= (4a)² - 2(4a)(3b) + (3b)²
= 16a² - 24ab + 9b²
Q13. (100 - 1)²
= (100)² - 2(100)(1) + (1)²
= 10000 - 200 + 1
= 9801
Q14. (3x² + 5xy - 2y²) + (x² - 3xy + 4y²)
= (3x² + x²) + (5xy - 3xy) + (-2y² + 4y²)
= 4x² + 2xy + 2y²
Q15. (x + 4)(x + 6) - (x + 2)(x + 3)
= (x² + 10x + 24) - (x² + 5x + 6)
= x² + 10x + 24 - x² - 5x - 6
= 5x + 18
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